<?xml version="1.0" encoding="UTF-8"?><rss version="2.0"
	xmlns:content="http://purl.org/rss/1.0/modules/content/"
	xmlns:dc="http://purl.org/dc/elements/1.1/"
	xmlns:atom="http://www.w3.org/2005/Atom"
	xmlns:sy="http://purl.org/rss/1.0/modules/syndication/"
		>
<channel>
	<title>Comments on: O Level Chemistry: Redox Reaction Question 4</title>
	<atom:link href="http://www.simplechemconcepts.com/chemistry-question-on-redox-reaction-q4/feed/" rel="self" type="application/rss+xml" />
	<link>http://www.simplechemconcepts.com/chemistry-question-on-redox-reaction-q4/</link>
	<description>O-Level Chemistry Made Easy</description>
	<lastBuildDate>Sat, 14 Jan 2012 03:43:17 +0000</lastBuildDate>
	<sy:updatePeriod>hourly</sy:updatePeriod>
	<sy:updateFrequency>1</sy:updateFrequency>
	<generator>http://wordpress.org/?v=3.0.4</generator>
	<item>
		<title>By: sean</title>
		<link>http://www.simplechemconcepts.com/chemistry-question-on-redox-reaction-q4/comment-page-1/#comment-388</link>
		<dc:creator>sean</dc:creator>
		<pubDate>Mon, 03 Mar 2008 16:18:36 +0000</pubDate>
		<guid isPermaLink="false">http://simplechemconcepts.com/chemistry-question-on-redox-reaction-q4/#comment-388</guid>
		<description>Hi Jennifer,

It is part of the learning curve. It is alrigt to make mistakes now.
Correcting them will do you well for your GCE O Level examinations.

Cheers
Sean</description>
		<content:encoded><![CDATA[<p>Hi Jennifer,</p>
<p>It is part of the learning curve. It is alrigt to make mistakes now.<br />
Correcting them will do you well for your GCE O Level examinations.</p>
<p>Cheers<br />
Sean</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Jen</title>
		<link>http://www.simplechemconcepts.com/chemistry-question-on-redox-reaction-q4/comment-page-1/#comment-379</link>
		<dc:creator>Jen</dc:creator>
		<pubDate>Fri, 29 Feb 2008 13:47:26 +0000</pubDate>
		<guid isPermaLink="false">http://simplechemconcepts.com/chemistry-question-on-redox-reaction-q4/#comment-379</guid>
		<description>Yes sir! i fully understand my mistake now. Thank you so much.

Best regards,
Jennifer</description>
		<content:encoded><![CDATA[<p>Yes sir! i fully understand my mistake now. Thank you so much.</p>
<p>Best regards,<br />
Jennifer</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: sean</title>
		<link>http://www.simplechemconcepts.com/chemistry-question-on-redox-reaction-q4/comment-page-1/#comment-312</link>
		<dc:creator>sean</dc:creator>
		<pubDate>Sun, 17 Feb 2008 17:50:08 +0000</pubDate>
		<guid isPermaLink="false">http://simplechemconcepts.com/chemistry-question-on-redox-reaction-q4/#comment-312</guid>
		<description>When a mixture of iron (II) oxide and carbon is heated, iron(II) oxide is 
reduced to iron and carbon is oxidized to carbon dioxide. The equation as:

FeO(s) + C(s) ---&gt; 2Fe(s) + CO2(g)

Carbon is oxidized. Thus (B) is Incorrect.

Carbon is acting as the reducing agent, thus (C) is Incorrect.

Carbon Dioxide is the end-product, not Carbon monoxide, thus (D) is Incorrect.

Fe2+ has indeed gained 2 electrons (-ve charges) to form Fe(s) metal.
Therefore, correct answer should be (A).

Hope this helps.
Sean

Note:
Jennifer - The answer that you provided in the question sheet (B) is Incorrect. Pls Note.</description>
		<content:encoded><![CDATA[<p>When a mixture of iron (II) oxide and carbon is heated, iron(II) oxide is<br />
reduced to iron and carbon is oxidized to carbon dioxide. The equation as:</p>
<p>FeO(s) + C(s) &#8212;> 2Fe(s) + CO2(g)</p>
<p>Carbon is oxidized. Thus (B) is Incorrect.</p>
<p>Carbon is acting as the reducing agent, thus (C) is Incorrect.</p>
<p>Carbon Dioxide is the end-product, not Carbon monoxide, thus (D) is Incorrect.</p>
<p>Fe2+ has indeed gained 2 electrons (-ve charges) to form Fe(s) metal.<br />
Therefore, correct answer should be (A).</p>
<p>Hope this helps.<br />
Sean</p>
<p>Note:<br />
Jennifer &#8211; The answer that you provided in the question sheet (B) is Incorrect. Pls Note.</p>
]]></content:encoded>
	</item>
</channel>
</rss>

<!-- Dynamic Page Served (once) in 0.501 seconds -->

