Comments on: O Level Chemistry: Redox Reactions http://www.simplechemconcepts.com/chemistry-question-redox-reactions-3/ Chemistry Made Easy Fri, 23 Jul 2010 03:40:12 -0500 http://wordpress.org/?v=2.8.4 hourly 1 By: SimpleChemConcepts | O Level Chemistry - More Questions on Redox http://www.simplechemconcepts.com/chemistry-question-redox-reactions-3/comment-page-1/#comment-3377 SimpleChemConcepts | O Level Chemistry - More Questions on Redox Thu, 25 Feb 2010 16:35:09 +0000 http://simplechemconcepts.com/chemistry-question-redox-reactions-3/#comment-3377 [...] Here is a question that we have discussed before on “Largest Change in Oxidation Numbers”: http://simplechemconcepts.com/chemistry-question-redox-reactions-3/ [...] [...] Here is a question that we have discussed before on “Largest Change in Oxidation Numbers”: http://simplechemconcepts.com/chemistry-question-redox-reactions-3/ [...]

]]> By: sean http://www.simplechemconcepts.com/chemistry-question-redox-reactions-3/comment-page-1/#comment-760 sean Wed, 16 Apr 2008 01:59:25 +0000 http://simplechemconcepts.com/chemistry-question-redox-reactions-3/#comment-760 Hi Gary, Hope all is well with your revision for Mid-Year exams. Spot On! Answer is indeed D and your approach towards such Redox question is correct. Like what Jennifer has mentioned, the stoichiometry of each species does not affect the O.S. since the equation is balanced. Keep up the good work! To your Academic Success in Chemistry Sean Founder & Master Trainer www.SimpleChemConcepts.com Hi Gary,

Hope all is well with your revision for Mid-Year exams.

Spot On! Answer is indeed D and your approach towards such Redox question is
correct.

Like what Jennifer has mentioned, the stoichiometry of each species does not
affect the O.S. since the equation is balanced.

Keep up the good work!

To your Academic Success in Chemistry
Sean
Founder & Master Trainer
http://www.SimpleChemConcepts.com

]]> By: sean http://www.simplechemconcepts.com/chemistry-question-redox-reactions-3/comment-page-1/#comment-759 sean Wed, 16 Apr 2008 01:56:18 +0000 http://simplechemconcepts.com/chemistry-question-redox-reactions-3/#comment-759 Hi Jennifer, Very good attempt indeed. The approach you use is correct. Just note that for (A), the O.S. for N should be +4 instead of +3. Check out the working again. Keep up the good work! To your Academic Success in Chemistry, Sean Founder & Master Trainer www.SimpleChemConcepts.com Hi Jennifer,

Very good attempt indeed. The approach you use is correct.

Just note that for (A), the O.S. for N should be +4 instead of +3. Check out the
working again.

Keep up the good work!

To your Academic Success in Chemistry,
Sean
Founder & Master Trainer
http://www.SimpleChemConcepts.com

]]> By: Gary http://www.simplechemconcepts.com/chemistry-question-redox-reactions-3/comment-page-1/#comment-592 Gary Fri, 21 Mar 2008 09:00:58 +0000 http://simplechemconcepts.com/chemistry-question-redox-reactions-3/#comment-592 My answer is D too.But i think the OS for N2 at the products in A should be +4 instead of +3 As Jen said,oxidation state for Nitrogen at the reactants are all +5 A: The OS for N2 at products is +4 so the change of OS is 1. B: The OS for N2 at products is +2 so the change of OS is 3. C: The OS for N2 at products is +1 so the change of OS is 4 D:The OS for N2 at products is -3 so the change of OS is 8 My answer is D too.But i think the OS for N2 at the products in A should be +4 instead of +3

As Jen said,oxidation state for Nitrogen at the reactants are all +5

A: The OS for N2 at products is +4 so the change of OS is 1.
B: The OS for N2 at products is +2 so the change of OS is 3.
C: The OS for N2 at products is +1 so the change of OS is 4
D:The OS for N2 at products is -3 so the change of OS is 8

]]> By: Jen http://www.simplechemconcepts.com/chemistry-question-redox-reactions-3/comment-page-1/#comment-587 Jen Fri, 21 Mar 2008 04:28:10 +0000 http://simplechemconcepts.com/chemistry-question-redox-reactions-3/#comment-587 Hello. My answer would be D For A, B, C, D : initial oxidation state (O.S) of Nitrogen = +5 irregardless of the coefficient of NO3^-1 A: final O.S of Nitrogen = +3 hence, change= +3-(+5) = -2 B: final O.S of Nitrogen = +2 hence, change = +2 - (+5) = -3 C: final O.S of Nitrogen= +1 hence, change = +1 - (+5) = -4 D: final O.S of Nitrogen = -3 hence, change = -3 + - (+5) = -8 Hello.

My answer would be D

For A, B, C, D : initial oxidation state (O.S) of Nitrogen = +5
irregardless of the coefficient of NO3^-1

A: final O.S of Nitrogen = +3
hence, change= +3-(+5) = -2

B: final O.S of Nitrogen = +2
hence, change = +2 – (+5) = -3

C: final O.S of Nitrogen= +1
hence, change = +1 – (+5) = -4

D: final O.S of Nitrogen = -3
hence, change = -3 + – (+5) = -8

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