Halo, Try this one…on Reduction & Oxidation (Redox Reactions).
Q) A drop of solution S turns acidified orange potassium dichromate (VI) to green chromium (III) ions. What must solution S contain?
A) An acid
B) An oxidizing agent
C) A reducing agent
D) A substance that can be oxidized
Come on students…. Leave your suggested answer in the “Comments” section below.
Rgds,
Sean
Is it C?
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Orange potassium dichromate (VI) is reduced to green chromium (III) ions, so it’s an oxidizing agent.
Hence, the solution must be a reducing agent…
C?
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I think the answer is C.. by the way, can I have the link that was removed in the comments in the post on Fats and Terylene?
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i think its C too.
S reduces the orange potassium dichromate (VI) to green potassium dichromate (III),
hence, S must be a reducing agent.
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Well Done both.
Answers is indeed C. Some students tends to have problems when it comes to Reducing and Oxidizing Agents.
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