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	<title>Comments on: O Level Chemistry Questions &#8211; Qualitative Analysis (QA) / SPA Tips</title>
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		<title>By: alwaysLovely</title>
		<link>http://www.simplechemconcepts.com/chemistry-questions-2/comment-page-1/#comment-29</link>
		<dc:creator>alwaysLovely</dc:creator>
		<pubDate>Fri, 14 Sep 2007 02:34:00 +0000</pubDate>
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		<description>Q21) Answer is Yellow color. At ph5, Phenolphthalein will remain colorless, Methyl orange will be yellow and bromothymol blue will be yellow too. As such, with equal volume, the overal color will be yellow in color for the solution. &lt;br/&gt; &lt;br/&gt;Q22) See below for all 4 choices and answer through elimination:&lt;br/&gt;A) Sodium carbonate will be formed from carbon dioxide reacting with NaOH, which is soluble in water. As such, no Visible Change will be observed,&lt;br/&gt;B) Chlorine gas will react with Potassium Iodide (Colorless solution) to form Iodine (Brown) and Potassium Chloride. In this reaction, Iodide ions are oxidized to form Iodine gas. Visible color change from colorless to Brownish solution. &lt;br/&gt;C) Ammonia gas reacts with Hydrochloric acid to form ammonium salt, in this one -NH4Cl, which is soluble in water due to their ionic nature, As such, no visible change.&lt;br/&gt;D) No known reaction mechanism between SO2 and Iron (II) Sulphate.&lt;br/&gt;Thus answer should be (B).&lt;br/&gt; &lt;br/&gt;Q23) For Potassium Carbonate solution reacting with Sample of Tap Water. Question is testing you on the ions that is present in the tap water.&lt;br/&gt;Potassium carbonate are soluble in water and thus looks colorless, as in all solutions.&lt;br/&gt;Do elimination again:&lt;br/&gt;Bromide ions -&gt; formed KBr which is soluble -&gt; no visible change&lt;br/&gt;Magnesium ions -&gt; formed MgCO3 which is insoluble in water - Visible change with precipitation&lt;br/&gt;Ammonium ions - &gt; formed NH4CO3 which is soluble in water -&gt; no visible change&lt;br/&gt;Sulphate ions -&gt; formed K2SO4 which is soluble in water -&gt; no visible change&lt;br/&gt;Thus answer should be (B).&lt;br/&gt; &lt;br/&gt;Q24) For H2S reacting with FeCl3 solution,&lt;br/&gt;It involves the reduction of Iron(III)Chloride with Hydrogen sulfide.&lt;br/&gt;It reduces the yellow acidified Iron(III)Chloride to green Fe2+ with the precipitation of Sulfur.&lt;br/&gt; &lt;br/&gt;Q25) On this question: Iron + Sodium Oxide, do you have more information as in the reaction paramaters, conditions, etc?? Bcos some reactions will occur in controlled high temp, pressure conditions.&lt;br/&gt;Do let me know more details. Theoretically, at room temp and without any additives - i do not see them reacting.</description>
		<content:encoded><![CDATA[<p>Q21) Answer is Yellow color. At ph5, Phenolphthalein will remain colorless, Methyl orange will be yellow and bromothymol blue will be yellow too. As such, with equal volume, the overal color will be yellow in color for the solution. </p>
<p>Q22) See below for all 4 choices and answer through elimination:<br />A) Sodium carbonate will be formed from carbon dioxide reacting with NaOH, which is soluble in water. As such, no Visible Change will be observed,<br />B) Chlorine gas will react with Potassium Iodide (Colorless solution) to form Iodine (Brown) and Potassium Chloride. In this reaction, Iodide ions are oxidized to form Iodine gas. Visible color change from colorless to Brownish solution. <br />C) Ammonia gas reacts with Hydrochloric acid to form ammonium salt, in this one -NH4Cl, which is soluble in water due to their ionic nature, As such, no visible change.<br />D) No known reaction mechanism between SO2 and Iron (II) Sulphate.<br />Thus answer should be (B).</p>
<p>Q23) For Potassium Carbonate solution reacting with Sample of Tap Water. Question is testing you on the ions that is present in the tap water.<br />Potassium carbonate are soluble in water and thus looks colorless, as in all solutions.<br />Do elimination again:<br />Bromide ions -> formed KBr which is soluble -> no visible change<br />Magnesium ions -> formed MgCO3 which is insoluble in water &#8211; Visible change with precipitation<br />Ammonium ions &#8211; > formed NH4CO3 which is soluble in water -> no visible change<br />Sulphate ions -> formed K2SO4 which is soluble in water -> no visible change<br />Thus answer should be (B).</p>
<p>Q24) For H2S reacting with FeCl3 solution,<br />It involves the reduction of Iron(III)Chloride with Hydrogen sulfide.<br />It reduces the yellow acidified Iron(III)Chloride to green Fe2+ with the precipitation of Sulfur.</p>
<p>Q25) On this question: Iron + Sodium Oxide, do you have more information as in the reaction paramaters, conditions, etc?? Bcos some reactions will occur in controlled high temp, pressure conditions.<br />Do let me know more details. Theoretically, at room temp and without any additives &#8211; i do not see them reacting.</p>
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		<title>By: lien</title>
		<link>http://www.simplechemconcepts.com/chemistry-questions-2/comment-page-1/#comment-27</link>
		<dc:creator>lien</dc:creator>
		<pubDate>Wed, 12 Sep 2007 14:34:00 +0000</pubDate>
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		<description>HAHAHAHAHA. IM a ALEVEL student! not O! LOL. Anyway, nice! Wish there was this blog 2 years ago. =). Any tips for a alevel student?</description>
		<content:encoded><![CDATA[<p>HAHAHAHAHA. IM a ALEVEL student! not O! LOL. Anyway, nice! Wish there was this blog 2 years ago. =). Any tips for a alevel student?</p>
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		<title>By: lijun(:</title>
		<link>http://www.simplechemconcepts.com/chemistry-questions-2/comment-page-1/#comment-21</link>
		<dc:creator>lijun(:</dc:creator>
		<pubDate>Wed, 12 Sep 2007 07:26:00 +0000</pubDate>
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		<description>&lt;i&gt;What is observed when hydrogen sulphide gas is reacted with iron(III) chloride solution?&lt;/i&gt;&lt;br/&gt;&lt;br/&gt;&lt;b&gt;H2S(g) + 2FeCl3(aq)-&gt; 2FeCl2(aq) + 2HCl(aq) + S(s)&lt;br/&gt;&lt;br/&gt;so light yellow deposits will be seen. also, the reddish-brown solution changes colour to become a green solution.&lt;/b&gt;&lt;br/&gt;&lt;br/&gt;&lt;br/&gt;&lt;br/&gt;&lt;br/&gt;&lt;i&gt;What happens when iron is heated with sodium oxide?&lt;/i&gt;&lt;br/&gt;&lt;br/&gt;actually, i think you&#039;re right that there&#039;s no reaction. but since it&#039;s a 5m question, i expect they want to to explain why there isn&#039;t a reaction.&lt;br/&gt;&lt;br/&gt;for example, sodium is more higher in the reactivity series, it has a greater tendency to form its positive ions. Iron has less tendency to form iron(II) ions, hence cannot displace sodium from the oxide.&lt;br/&gt;&lt;br/&gt;btw. is it correct, that sodium oxide is a very stable compound, as there&#039;s a stronger attraction of the nucleus on the electron(as valance electron quite near to nucleus)&lt;br/&gt;&lt;br/&gt;&lt;br/&gt;please do point out my mistakes if i have any misconceptions.</description>
		<content:encoded><![CDATA[<p><i>What is observed when hydrogen sulphide gas is reacted with iron(III) chloride solution?</i></p>
<p><b>H2S(g) + 2FeCl3(aq)-> 2FeCl2(aq) + 2HCl(aq) + S(s)</p>
<p>so light yellow deposits will be seen. also, the reddish-brown solution changes colour to become a green solution.</b></p>
<p><i>What happens when iron is heated with sodium oxide?</i></p>
<p>actually, i think you&#8217;re right that there&#8217;s no reaction. but since it&#8217;s a 5m question, i expect they want to to explain why there isn&#8217;t a reaction.</p>
<p>for example, sodium is more higher in the reactivity series, it has a greater tendency to form its positive ions. Iron has less tendency to form iron(II) ions, hence cannot displace sodium from the oxide.</p>
<p>btw. is it correct, that sodium oxide is a very stable compound, as there&#8217;s a stronger attraction of the nucleus on the electron(as valance electron quite near to nucleus)</p>
<p>please do point out my mistakes if i have any misconceptions.</p>
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		<title>By: lijun(:</title>
		<link>http://www.simplechemconcepts.com/chemistry-questions-2/comment-page-1/#comment-18</link>
		<dc:creator>lijun(:</dc:creator>
		<pubDate>Wed, 12 Sep 2007 07:01:00 +0000</pubDate>
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		<description>hey.. just checking if these are correct.&lt;br/&gt;&lt;br/&gt;Q20 D&lt;br/&gt;&lt;br/&gt;cos i don&#039;t think the indicators actually react with one another. and at pH5, both methyl orange &amp; bromothymol blue are yellow, and phenolphthalein is colourless.&lt;br/&gt;&lt;br/&gt;&lt;br/&gt;Q21 B&lt;br/&gt;&lt;br/&gt;chlorine displace iodide ions.&lt;br/&gt;ionic eqn: Cl2 + 2I- -&gt; I2 + Cl2&lt;br/&gt;so the solution will turn from yellowish-green to reddish brown.&lt;br/&gt;&lt;br/&gt;&lt;br/&gt;Q22 B&lt;br/&gt;&lt;br/&gt;cos MgCO3 is insoluble. other compounds such as KBr, NH4CO3 &amp; K2SO4 are soluble.&lt;br/&gt;&lt;br/&gt;&lt;br/&gt;&lt;br/&gt;-lijun(:</description>
		<content:encoded><![CDATA[<p>hey.. just checking if these are correct.</p>
<p>Q20 D</p>
<p>cos i don&#8217;t think the indicators actually react with one another. and at pH5, both methyl orange &#038; bromothymol blue are yellow, and phenolphthalein is colourless.</p>
<p>Q21 B</p>
<p>chlorine displace iodide ions.<br />ionic eqn: Cl2 + 2I- -> I2 + Cl2<br />so the solution will turn from yellowish-green to reddish brown.</p>
<p>Q22 B</p>
<p>cos MgCO3 is insoluble. other compounds such as KBr, NH4CO3 &#038; K2SO4 are soluble.</p>
<p>-lijun(:</p>
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