Comments on: O Level Chemistry Questions – Mole Calculations / Mole Concepts

By: sevde

sevde — Fri, 16 Dec 2011 07:23:30 +0000

can u pls expalin why KI is the limiting factor???

By: Natalie

Natalie — Wed, 13 Oct 2010 15:48:50 +0000

For question part d, just calculate the number of moles of KNO3 using mole ratio of the equation and divide by the the total volume of aqueous solution which is 500cm3.

remember to convert it to dm3.

By: Natalie

Natalie — Wed, 13 Oct 2010 15:47:37 +0000

No. of Moles of Pb(NO3)2 = 20 / (207 + 2x(14+16×3)) = 0.0604229

No. of Moles of KI = 20 / (39 +127) = 0.1204819

Based on the equation, by right, 0.0604559 mol of Pb(NO3)2 require 0.1208458 mol of KI. Since, no of moles of KI is 0.1204819 only, KI is the limiting reactant.

By: pinkk

pinkk — Sat, 18 Sep 2010 13:52:58 +0000

why isnt the limiting reagent is Pb(NO3)? please reply asapppppp

By: Kinza

Kinza — Wed, 14 Oct 2009 20:20:50 +0000

wow some good questions, could u please send me the working out for question (d) What is the concentration of potassium nitrate in the reaction mixture when the reaction is completed? Give your answers in mol/dm3. (2 marks)! because i dont know where i am going wrong! thank you
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