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	<title>Comments on: O Level Chemistry &#8211; Mole Calculation + Organic Chemistry Question</title>
	<atom:link href="http://www.simplechemconcepts.com/o-level-chemistry-mole-calculation-organic-chemistry-question/feed/" rel="self" type="application/rss+xml" />
	<link>http://www.simplechemconcepts.com/o-level-chemistry-mole-calculation-organic-chemistry-question/</link>
	<description>Chemistry Made Easy</description>
	<lastBuildDate>Sat, 04 Sep 2010 07:35:27 -0500</lastBuildDate>
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		<title>By: yumi</title>
		<link>http://www.simplechemconcepts.com/o-level-chemistry-mole-calculation-organic-chemistry-question/comment-page-1/#comment-6651</link>
		<dc:creator>yumi</dc:creator>
		<pubDate>Sat, 08 May 2010 16:32:15 +0000</pubDate>
		<guid isPermaLink="false">http://simplechemconcepts.com/?p=745#comment-6651</guid>
		<description>(a)10 cm3
(b)90 cm3
(c)60 cm3
(d)C3H6
Could you tell me if my answers are goo?</description>
		<content:encoded><![CDATA[<p>(a)10 cm3<br />
(b)90 cm3<br />
(c)60 cm3<br />
(d)C3H6<br />
Could you tell me if my answers are goo?</p>
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	<item>
		<title>By: yumi</title>
		<link>http://www.simplechemconcepts.com/o-level-chemistry-mole-calculation-organic-chemistry-question/comment-page-1/#comment-6647</link>
		<dc:creator>yumi</dc:creator>
		<pubDate>Sat, 08 May 2010 14:04:01 +0000</pubDate>
		<guid isPermaLink="false">http://simplechemconcepts.com/?p=745#comment-6647</guid>
		<description>(a)10 cm3
(b)90 cm3
(c)60 cm3
(d)C3H6</description>
		<content:encoded><![CDATA[<p>(a)10 cm3<br />
(b)90 cm3<br />
(c)60 cm3<br />
(d)C3H6</p>
]]></content:encoded>
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	<item>
		<title>By: M.A Rajagopal</title>
		<link>http://www.simplechemconcepts.com/o-level-chemistry-mole-calculation-organic-chemistry-question/comment-page-1/#comment-6440</link>
		<dc:creator>M.A Rajagopal</dc:creator>
		<pubDate>Wed, 05 May 2010 10:23:59 +0000</pubDate>
		<guid isPermaLink="false">http://simplechemconcepts.com/?p=745#comment-6440</guid>
		<description>When a hydrocarbon is completely burnt the products will be carbon dioxide and water and unreacted oxygen (in this case)
Nothing is mentioned about water or steam in the question.
Could you please explain.
Thanks.
Rajagopal</description>
		<content:encoded><![CDATA[<p>When a hydrocarbon is completely burnt the products will be carbon dioxide and water and unreacted oxygen (in this case)<br />
Nothing is mentioned about water or steam in the question.<br />
Could you please explain.<br />
Thanks.<br />
Rajagopal</p>
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	<item>
		<title>By: Saud</title>
		<link>http://www.simplechemconcepts.com/o-level-chemistry-mole-calculation-organic-chemistry-question/comment-page-1/#comment-3261</link>
		<dc:creator>Saud</dc:creator>
		<pubDate>Fri, 19 Feb 2010 17:05:20 +0000</pubDate>
		<guid isPermaLink="false">http://simplechemconcepts.com/?p=745#comment-3261</guid>
		<description>a)    10..........coz it is mentioned after soda lime was introduced 10 cm was left
b)    90............simply 100-10=90
c)    60............10 was oxygen rest 60 removed by soda lime and 10+60=70 that was given as the total left over
d)    sorry...............im not certain about this one so i request to please tell me about my this work and any correction that need to be made.</description>
		<content:encoded><![CDATA[<p>a)    10&#8230;&#8230;&#8230;.coz it is mentioned after soda lime was introduced 10 cm was left<br />
b)    90&#8230;&#8230;&#8230;&#8230;simply 100-10=90<br />
c)    60&#8230;&#8230;&#8230;&#8230;10 was oxygen rest 60 removed by soda lime and 10+60=70 that was given as the total left over<br />
d)    sorry&#8230;&#8230;&#8230;&#8230;&#8230;im not certain about this one so i request to please tell me about my this work and any correction that need to be made.</p>
]]></content:encoded>
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	<item>
		<title>By: rija</title>
		<link>http://www.simplechemconcepts.com/o-level-chemistry-mole-calculation-organic-chemistry-question/comment-page-1/#comment-2295</link>
		<dc:creator>rija</dc:creator>
		<pubDate>Tue, 05 May 2009 18:52:33 +0000</pubDate>
		<guid isPermaLink="false">http://simplechemconcepts.com/?p=745#comment-2295</guid>
		<description>i don&#039;t understand it.Sean explain it in detail......</description>
		<content:encoded><![CDATA[<p>i don&#8217;t understand it.Sean explain it in detail&#8230;&#8230;</p>
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