O Level Chemistry: Mole Calculations – Limiting & Excess Reactants
28 Mar
Posted by: sean in: Chemistry Notes & Tips
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In the previous blogpost, we have discussed on the concepts surrounding Limiting & Excess Reactants, as well as look into one example.
Now, it is time for you to try out a question on your own.
Quick Check 1:
In the presence of a catalyst and at suitable temperature, 200cm3 of sulfur dioxide was reacted with 200cm3 of oxygen to form a gaseous product, sulfur trioxide. What is the total volume of gases remaining in the reaction vessel after the reaction? (2 marks)Clue: You need to write a balanced chemical equation first!
PS: Do write down your answer in the comment section below. Showing of working is even better for your learning purpose.
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2 Responses
heeko
31|Mar|2010 1According to the equation the gases reacted in 1:2. Thet is, one volume of oxygen reacted with two volumes of sulphur dioxide, so 100 cm3 oxygen will react with 200 cm3 of sulphur dioxide, making it the limiting reactant and so 100 cm3 of oxygen will be left behind unreacted!
Reply
Sarmast Bilawal Khuhro
03|Apr|2010 2according to the Equation:
2SO2 + O2 2SO3
2 Moles of Sulfur Dioxide react with 1 Mole of Oxygen
2:1
200cm3 of SO2 would be used up leaving behind 100cm3 of Oxygen
Reply
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