http://www.simplechemconcepts.com/o-level-chemistry-mole-calculations-limiting-excess-reactants-2/ O-Level Chemistry Made Easy Sat, 14 Jan 2012 03:43:17 +0000 hourly 1 http://wordpress.org/?v=3.0.4 http://www.simplechemconcepts.com/o-level-chemistry-mole-calculations-limiting-excess-reactants-2/comment-page-1/#comment-4371 Sarmast Bilawal Khuhro Fri, 02 Apr 2010 19:42:34 +0000 http://www.simplechemconcepts.com/?p=2588#comment-4371 according to the Equation: 2SO2 + O2 2SO3 2 Moles of Sulfur Dioxide react with 1 Mole of Oxygen 2:1 200cm3 of SO2 would be used up leaving behind 100cm3 of Oxygen according to the Equation:
2SO2 + O2 2SO3
2 Moles of Sulfur Dioxide react with 1 Mole of Oxygen
2:1
200cm3 of SO2 would be used up leaving behind 100cm3 of Oxygen

]]> http://www.simplechemconcepts.com/o-level-chemistry-mole-calculations-limiting-excess-reactants-2/comment-page-1/#comment-4363 heeko Wed, 31 Mar 2010 13:59:07 +0000 http://www.simplechemconcepts.com/?p=2588#comment-4363 According to the equation the gases reacted in 1:2. Thet is, one volume of oxygen reacted with two volumes of sulphur dioxide, so 100 cm3 oxygen will react with 200 cm3 of sulphur dioxide, making it the limiting reactant and so 100 cm3 of oxygen will be left behind unreacted! According to the equation the gases reacted in 1:2. Thet is, one volume of oxygen reacted with two volumes of sulphur dioxide, so 100 cm3 oxygen will react with 200 cm3 of sulphur dioxide, making it the limiting reactant and so 100 cm3 of oxygen will be left behind unreacted!

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