Comments on: O Level Chemistry – Strategies to Predict Products of Electrolysis for Aqueuous Solutions http://www.simplechemconcepts.com/o-level-chemistry-strategies-to-predict-products-of-electrolysis-for-aqueuous-solutions/ O-Level Chemistry Made Easy Sat, 14 Jan 2012 03:43:17 +0000 hourly 1 http://wordpress.org/?v=3.0.4 By: Adnan http://www.simplechemconcepts.com/o-level-chemistry-strategies-to-predict-products-of-electrolysis-for-aqueuous-solutions/comment-page-1/#comment-7259 Adnan Sun, 02 Jan 2011 13:43:23 +0000 http://simplechemconcepts.com/?p=576#comment-7259 U hav cleared my basic concepts, CUD U PLEASE TELME THE PRODUCTS OF ELECTROLYSIS OF Cucl2 WITH PT ELECTRODE in detail U hav cleared my basic concepts, CUD U PLEASE TELME THE PRODUCTS OF ELECTROLYSIS OF Cucl2 WITH PT ELECTRODE in detail

]]> By: rai http://www.simplechemconcepts.com/o-level-chemistry-strategies-to-predict-products-of-electrolysis-for-aqueuous-solutions/comment-page-1/#comment-7223 rai Fri, 17 Dec 2010 06:09:18 +0000 http://simplechemconcepts.com/?p=576#comment-7223 one more thing can any one please suggest me a way for quick revision and how to make isomers one more thing can any one please suggest me a way for quick revision
and how to make isomers

]]> By: rai http://www.simplechemconcepts.com/o-level-chemistry-strategies-to-predict-products-of-electrolysis-for-aqueuous-solutions/comment-page-1/#comment-7222 rai Fri, 17 Dec 2010 06:07:54 +0000 http://simplechemconcepts.com/?p=576#comment-7222 hey there is a best and easy way to learn reactivity series....it is like this please =potassium send =sodium cats =calcium monkeys =magnesium and =aluminium zebras =zinc in =iron large =lead huge =hydrogen cages =cooper make =mercury sure =silver padlocked =platinum hey there is a best and easy way to learn reactivity series….it is like this
please =potassium
send =sodium
cats =calcium
monkeys =magnesium
and =aluminium
zebras =zinc
in =iron
large =lead
huge =hydrogen
cages =cooper
make =mercury
sure =silver
padlocked =platinum

]]> By: sara sousou http://www.simplechemconcepts.com/o-level-chemistry-strategies-to-predict-products-of-electrolysis-for-aqueuous-solutions/comment-page-1/#comment-7211 sara sousou Mon, 13 Dec 2010 15:22:48 +0000 http://simplechemconcepts.com/?p=576#comment-7211 if aqueous potassium bromide was electrolysed which ion would move to the anode?? is it OH- or bromide? if bromide does it mean that bromide is concentrated since OH is lower in the series and it should be the one discharged. if aqueous potassium bromide was electrolysed which ion would move to the anode?? is it OH- or bromide? if bromide does it mean that bromide is concentrated since OH is lower in the series and it should be the one discharged.

]]> By: aec http://www.simplechemconcepts.com/o-level-chemistry-strategies-to-predict-products-of-electrolysis-for-aqueuous-solutions/comment-page-1/#comment-7071 aec Mon, 04 Oct 2010 02:31:13 +0000 http://simplechemconcepts.com/?p=576#comment-7071 Hi Sean, I refer to your reply to Jasmine above. If OH- is at the bottom of the electrochemical series and we're talking about a dilute sodium chloride solution, oxygen gas is produced at the anode as a result of the position of ions in the electrochemical series, but if it is concentrated sodium chloride, then chlorine gas is produced as a result of the concentration factor. That aside, with reference to the electrochemical series for anions, whereby F- is at the top and OH- at the bottom, isn't the anions at the bottom more reactive hence easier to discharge in comparison to the anions above? So wouldn't OH- be more reactive than Cl-, hence the preference for OH- to be discharged (assuming dilute solution)? If something is not reactive, I assume that it the probability of it being discharged (transformed to something else) is smaller compared to one that is more reactive. I am getting contradicting information that the anions further up the series are more reactive than the ones at the bottom. I agree that F is reactive, that's why it becomes F- which is more stable, so to say that F- is reactive is not accurate is it? Look forward to your reply. Thank you! Hi Sean,
I refer to your reply to Jasmine above. If OH- is at the bottom of the electrochemical series and we’re talking about a dilute sodium chloride solution, oxygen gas is produced at the anode as a result of the position of ions in the electrochemical series, but if it is concentrated sodium chloride, then chlorine gas is produced as a result of the concentration factor.

That aside, with reference to the electrochemical series for anions, whereby F- is at the top and OH- at the bottom, isn’t the anions at the bottom more reactive hence easier to discharge in comparison to the anions above? So wouldn’t OH- be more reactive than Cl-, hence the preference for OH- to be discharged (assuming dilute solution)? If something is not reactive, I assume that it the probability of it being discharged (transformed to something else) is smaller compared to one that is more reactive.

I am getting contradicting information that the anions further up the series are more reactive than the ones at the bottom. I agree that F is reactive, that’s why it becomes F- which is more stable, so to say that F- is reactive is not accurate is it?

Look forward to your reply.
Thank you!

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