O Levels Chemistry Tips Blog Marathon – Day 3

25 Apr

Posted by: sean in: Chemistry Notes & Tips

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In yesterday (Day 2) post of “O Levels Chemistry Tips Blog Marathon” series, we have discussed on the important concepts that GCE O Levels Chemistry students need to know for Acids, Bases & Salts. There are also 2 basic multiple choice questions for you to attempt to see how much you understand about this chapters.

Today, we are going to look into 2 more questions on Acids, Bases & Salts, which potentially can be tricky questions for your school’s chemistry mid-year examinations.

Question 1: Based on the topic “Acids, Bases & Salts”

Which salt can be prepared by an acid-alkali titration method?

A. Ammonium sulfate
B. Copper (II) sulfate
C. Iron (II) sulfate
D. Zinc sulfate

Clue: 1st step is to determine the solubility of the salt.

and

Question 2: Based on the topic “Acids, Bases & Salts”

Which of the following particles are NOT present in a carbonic acid solution?

A. CO32-(aq)
B. H+(aq)
C. CO2(aq)
D. H2CO3(aq)

Clue: You need to understand on the Dissociation of Acids

As mentioned in many of my posts, “Once the student is ready, the teacher will appear” – this means that i will give my suggested answers and reasonings once i see chemistry students / readers participating in the discussion.

PS: Attempt the 2 questions above and leave down your answers & reasonings in the “Leave A Reply” below.

PPS: If you have any chemistry questions that would like us to discuss it on this humble Chemistry Blogsite, please send it to admin@SimpleChemConcepts.com

Stay tuned for the next post on Bondings & Structural Properties!

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10 Responses

Dcma1993
26|Apr|2009 1

1. Should be A. All SPA (sodium, potassium, ammonium) and Group 1 metal salts should be prepared using titration as long as they are soluble. Ammonium Sulfate is soluble.

2. C. Carbonic acid is a weak acid, hence it does not dissociate fully. Hence there should be Hydrogen ions, Carbonate ions and some H2CO3 molecules in the mixture. By elimination, CO2 should not be present.

Reply
sean Reply:
July 8th, 2009 at 11:51 pm
Well Done!

Keep up the good work!

If there is any Chemistry Question that you would like us to discuss it here,
do not hesitate to send me the question to my email at sean@SimpleChemConcepts.com.

Take care and study hard =)
Sean

Reply
hina
28|Apr|2009 2

sir can i have notes on organic chemistry and its processes?please

Reply
sean Reply:
July 8th, 2009 at 11:53 pm
Hi,

Organic Chemistry is a broad subject title that can contain many mini topics such as:
1. Fuels
2. Intro to Organic Chemistry
3. Alkanes
4. Alkenes
5. Alcohols
6. Carboxylic Acids
7. Esters
8. Macromoelcules / Polymers

I would suggest that you search for the specific keywords at the SEARCH field on the
right hand side of this blog.

To Your Academic Success in Chemistry,
Sean =)

Reply
hina
30|Apr|2009 3

the answer of first question is “A” because all ammonium salts are soluble so this
salt “ammonium sulphate” is soluble.
the answer of second question seem to be “a” again because the rest seems
to be correct fro me

Reply
sean Reply:
July 8th, 2009 at 11:54 pm
Hi,

You are spot on for Question 1, but answer for Question 2 is incorrect.

Check out my suggested answers below.

Cheers
Sean =)

Reply
Tan Kai Lin
06|Jul|2009 4

Myfirst answer is D, second answer is B.

Reply
sean Reply:
July 8th, 2009 at 11:56 pm
Hi Kai Lin,

I am glad to see you reading this chemistry blogsite and participating in answering the questions.

Check out my suggested answers below.

Keep reading through the older “archives” in this blog to learn more.

To Your Academic Success in Chemistry,
Sean =)

Reply
sean
09|Jul|2009 5

Hi Everyone,

Answer for Question 1: (A)

Suggested Reason: The 1st thing to look at is to decide the Solubility of Salts.
All SPA (Sodium, Potassium & Ammonium) salts are soluble in water. Next, Decide what type of reactants you could use. For ammonium sulfate, the common reagents you can used is Sulfuric Acid & Ammonium Hydroxide (more commonly known as Aqueous Ammonia or Ammonia Solution).

Answer for Question 2: (C)

Suggested Reason: Carbonic acid is a weak acid, hence it dissociate partially only. There should be Hydrogen ions (H+), Carbonate ions (CO32-) and some H2CO3 molecules in the mixture. By elimination, CO2 should not be present and thus the answer.

H2CO3 < => 2H+ + CO32-

Partial Dissociation of Carbonic Acid

Hope this information is clear to you.

To Your Academic Success in Chemistry,
Sean Chua =)
Master Trainer & Author
WINNERS Education Group

Reply
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