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O Level Chemistry & IP Chemistry Notes by 10 Year Series Author – Chemistry Specialist

O Level Chemistry & IP Chemistry Notes by 10 Year Series Author - Chemistry Specialist

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O Level Chemistry: Mole Concepts / Chemical Calculations

Below is a common Mole Calculation question on finding the Empirical and then Molecular Formulae of a compound. Do make sure you can amswer this one as it is a very common examination question that warrant a couple of important marks. I said Important because this is not a really tough question and we should score full marks for it.

Example:
Compound Y contains 40.0% carbon, 6.6% hydrogen and 53.3% oxygen. It has a relative molecular mass of 180. What is the molecular formula of Y?

Tips:
1st Step ? Find the mass of each component by taking a basis of 100g
2nd Step ? Find the empirical formula
3rd Step ? Find the molecular formula

Please leave your working and answers in the “Comment” section directly below this post.

PS: “Either You Practice & Utilize It, or You Loose It!”

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Sean Chua
Sean Chua
Winners Education Centre Pte. Ltd.
Many know me as the Ten Year Series book author for JC A-Level H2 Chemistry and O-Level Pure Chemistry. My 19+ years of coaching experience (since 1999) with more than 1500 students from 180+ JCs and Secondary Schools has allowed me to understand the true reasons why students are not able to perform well in Chemistry. Most importantly, my strength lies in using everyday analogies (even grandmothers can understand!) to simplify abstract concepts. Also, my teaching methodology has been designed to be fun, enjoyable and effective for my students. If you want to have an enjoyable time learning Chemistry and being motivated to excel in Chemistry, contact me today at 98287357

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Comments

  1. botlhe says

    April 26, 2011 at 5:26 am

    thanx helped a lot

  2. sean says

    March 9, 2008 at 11:44 pm

    You are spot on. The molecular formulae is indeed C6H12O6.
    This is actually a Sugar compound.

  3. Jennifer says

    March 8, 2008 at 11:50 pm

    Element C H O
    Mass of Element 40 6.6 53.3
    Ar 12 1 16
    no. of mol 3.33 6.6 3.33
    molar ratio 1 2 1

    hence empirical formula: CH2O

    n
    = 180/(12+2+16=30)
    =6

    therefore molecular formula of Y: C6H12O6

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