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O Level Chemistry – Mini Series on Tough MCQs Part 4

Most of you would have finished most of O Levels Papers by now, and left with Paper 1 of Chemistry, Biology, Physics and Combine Science (Chem/Bio) or (Chem/Phy).

I realised that many students have started to have their holiday mood, and in fact already enjoying as though holiday has arrived.

Wait. Don’t get me wrong! Of course, it is important to relax awhile before their last papers, especially when their “last papers” are 1 week after the “second-last papers”. I can’t agree more that students should celebrate the little success, and enjoy abit of what they like to do during this one week, before their last papers. Students – You Have Been Working Hard! Kudos!

However, i must re-iterate that Paper 1 Examinations hold alot of marks for your subject. For example, Chemistry Paper 1 has a weightage of 40 marks which is translated to be 30% of your final Chemistry Grade. That is ALOT of marks to Score! So while you are enjoying now, do spend a few days to re-cap and practice more MCQs questions before your Chemistry Paper 1 next week.

Here is a couple of tricky MCQ questions that i have came across:

(Click image to have clearer view)

Question 1:
proton-number-1

PS:Remember to try out the questions and leave your answers and reasoning in the section “Leave A Reply” below

Question 2:
stability-of-metal-carbonates

Question 3:
reducing-agents-in-blast-furnace

Related Articles:

  • O Level Chemistry Question – Organic Chemistry (Alcohol)
  • O-Level Chemistry: Score 100% MCQ Workshop (6th Year)
  • O Level Chemistry – Mini Series on Tough MCQs Part 3
  • O Level Chemistry – Mini Series on Tough MCQs Part 1
  • Chemistry Tips: How to Revise for your GCE ‘O’ Level Chemistry Exams

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Comments

  1. Vidu says

    February 5, 2012 at 3:39 pm

    I think the answers are 1-c
    2-a
    3-c

  2. sam says

    November 11, 2011 at 9:00 pm

    so what is the correct answer?

  3. Matthew says

    November 10, 2011 at 11:45 pm

    For the portion of:
    ‘Carbon on the other hand reacts with Oxygen to form Carbon Dioxide so Oxygen changed from an oxidation state of 0 to 2- so it is reduced and Carbon should be a reducing agent’,
    rather than seeing it as oxygen losing 2 electrons, it can be seen as carbon gaining 2 oxygen atoms and therefore being oxidised.

  4. Fixxa says

    October 16, 2011 at 6:14 pm

    carbon monoxide is the reducing agent because it reduces Fe2O3 to molten iron (Fe) and takes up oxygen itself and becomes carbon dioxide. This is why it is the reducing agent.

  5. A says

    November 9, 2010 at 2:54 pm

    I agree with the other people on the first two questions. But I’m sorry but why is the answer for the last question B? Carbon Dioxide reacts with Carbon at high temperatures to form Carbon Monoxide in the chemical reaction CO2(g)+C(s)=2CO(g) so Carbon dioxide causes the Carbon atom to change from an oxidation state of 0 to 2+ so it has been oxidised and Carbon Dioxide should be an oxidising agent. Carbon on the other hand reacts with Oxygen to form Carbon Dioxide so Oxygen changed from an oxidation state of 0 to 2- so it is reduced and Carbon should be a reducing agent. The answer should be C. Will someone please clarify?

  6. khalid says

    January 13, 2010 at 10:33 pm

    well done !!!

  7. Waleee bin qasim says

    November 21, 2009 at 9:48 pm

    Thats 1C 2A 3 B among these q.no 1 was a bit imaginary,but easily resolved

  8. Karrington says

    November 7, 2009 at 1:55 pm

    I think its C, A and B.

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