O Level Chemistry: Challenging Mole Calculation Questions

Recently, i received several emails and comments from readers (students) to share more challenging Mole Calculations (or Mole Concepts) questions in this chemistry blog.  So here we go………..

Question:

What would be the concentration of the hydrochloric acid produced if all the hydrogen chloride gas from the reaction between 50 g of pure sulfuric acid and an excess of sodium chloride was collected in water, and the solution made up to a volume of 400 cm3 of water?

Based on equation: NaCl(s)   +   H2SO4(aq)    –>   NaHSO4(s)   +   HCl(g)

Now, try it out and leave your suggested answer (and possibly your solution/steps) in the comment section below.

The best way to learn is NOT by reading or looking, instead it is by Taking Actions.

I look forward to seeing you answers. Cheers! Enjoy! =)

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14 Responses to O Level Chemistry: Challenging Mole Calculation Questions
  1. Chemistry genius
    May 9, 2010 | 1:41 pm

    50/98=0.5102
    0.5102/(400/1000)= 1.28mol/dm3

    Reply

  2. taimoor
    May 9, 2010 | 7:08 pm

    27.40 mol/dm3

    Reply

  3. Awesomus
    May 12, 2010 | 6:47 pm

    It’s 1.28 mol/dm3

    Reply

  4. budding chemist
    May 17, 2010 | 9:51 pm

    What would be the concentration of the hydrochloric acid produced if all the hydrogen chloride gas from the reaction between 50g of pure sulfuric acid and an excess of sodium chloride was collected in water, and the solution made up to a volume of 400 cm3 of water?

    Based on equation: NaCl(s) + H2SO4(aq) –> NaHSO4(s) + HCl(g)

    mole=50/(2+32+(16×4))=0.5102
    mol/dm3=0.5102/(400/1000)=1.28mol/dm3

    Reply

  5. Saud
    May 20, 2010 | 11:01 pm

    yeah i agree with the majority….
    its 1.28mol/dm3

    mass of sulfuric acid = 50g
    relative formula mass of sulfuric acid = 98
    so,
    moles of sulfuric acid = mass/molar mass
    = 50/98
    = 0.51 moles

    keeping in view the stoichometric ratios of the reactants and the products we get that one mole of sulfuric acid results one mole of HCl…

    given also that the solution was made upto 400 cm3
    that means that the moles of HCl in 400cm3 are 0.51

    how much will these be in 1000cm3 i-e 1dm3
    that is

    =1000/400 x0.51
    =1.275 moles in 1dm3
    approximating it to 2 decimal places

    concentration of HCl = 1.28 mol/dm3

    :)

    Reply

  6. Saud
    May 20, 2010 | 11:03 pm

    i don’t get that why others have divided 0.51 with 400/1000 …… ??

    guide me guys…………..

    Reply

    kazim Reply:

    its because the concentration is in mol./dm3, but the volume of water given is in cm3 so we divide it by 1000 to convert it into dm3. =D

    Reply

    Karl Reply:

    @Saud – you are correct, don’t worry.

    Reply

  7. abhishek
    May 23, 2010 | 6:40 pm

    1.28 mol/dm3

    Reply

    abel Reply:

    can you please be my personal tutor

    Reply

    sean Reply:

    Hi Abel,

    If you based in Singapore, you can consider our Chemistry Classes for O and A-Levels.
    Find out more information at http://www.WinnersEducation.com

    Regards,
    Sean Chua

    Reply

  8. yumi
    June 1, 2010 | 3:57 pm

    1.28 mol/dm3 (to 3 sf)

    Reply

  9. Vidushi
    February 27, 2011 | 9:36 pm

    Mr or H2SO4 = 98

    98g H2SO4 = 1 MOL
    50g H2SO4 = 0.51 MOL

    1 MOL H2SO4 = 1 MOL HCL
    0.51 MOL H2SO4 = 0.51 MOL HCL

    NO OF MOL HCL IN 40OCM^3 WATER = 0.51 MOL
    NO OF MOL HCL IN 100CM63 WATER = 1.275 MOL

    THEREFORE CONCENTRATION = 1.275mol/dm^3

    my method is rather kind of long but you can understand well right?

    Reply

  10. Abel
    May 4, 2011 | 12:26 am

    I feel it is really fun for you guys to early tackle questions,as for me I think I’m still far away,even if I have much passion.

    Reply

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