Recently, i received several emails and comments from readers (students) to share more challenging Mole Calculations (or Mole Concepts) questions in this chemistry blog. So here we go………..
Question:
What would be the concentration of the hydrochloric acid produced if all the hydrogen chloride gas from the reaction between 50 g of pure sulfuric acid and an excess of sodium chloride was collected in water, and the solution made up to a volume of 400 cm3 of water?
Based on equation: NaCl(s) + H2SO4(aq) –> NaHSO4(s) + HCl(g)
Now, try it out and leave your suggested answer (and possibly your solution/steps) in the comment section below.
The best way to learn is NOT by reading or looking, instead it is by Taking Actions.
I look forward to seeing you answers. Cheers! Enjoy! =)
Related Articles:
- O Level Chemistry – Determination of Ionic Equation & Spectator Ions
- O Levels Chemistry Questions – Mole Calculations / Mole Concepts
- O Level Chemistry: Mole Concepts / Chemical Calculations
- O Level Chemistry: Mole Calculations – Balanced Chemical & Ionic Equations
- O Level Chemistry: Mole Calculations / Preparation of Salts








50/98=0.5102
0.5102/(400/1000)= 1.28mol/dm3
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27.40 mol/dm3
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It’s 1.28 mol/dm3
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What would be the concentration of the hydrochloric acid produced if all the hydrogen chloride gas from the reaction between 50g of pure sulfuric acid and an excess of sodium chloride was collected in water, and the solution made up to a volume of 400 cm3 of water?
Based on equation: NaCl(s) + H2SO4(aq) –> NaHSO4(s) + HCl(g)
mole=50/(2+32+(16×4))=0.5102
mol/dm3=0.5102/(400/1000)=1.28mol/dm3
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yeah i agree with the majority….
its 1.28mol/dm3
mass of sulfuric acid = 50g
relative formula mass of sulfuric acid = 98
so,
moles of sulfuric acid = mass/molar mass
= 50/98
= 0.51 moles
keeping in view the stoichometric ratios of the reactants and the products we get that one mole of sulfuric acid results one mole of HCl…
given also that the solution was made upto 400 cm3
that means that the moles of HCl in 400cm3 are 0.51
how much will these be in 1000cm3 i-e 1dm3
that is
=1000/400 x0.51
=1.275 moles in 1dm3
approximating it to 2 decimal places
concentration of HCl = 1.28 mol/dm3
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i don’t get that why others have divided 0.51 with 400/1000 …… ??
guide me guys…………..
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kazim Reply:
May 23rd, 2010 at 9:25 pm
its because the concentration is in mol./dm3, but the volume of water given is in cm3 so we divide it by 1000 to convert it into dm3. =D
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Karl Reply:
May 25th, 2010 at 11:58 pm
@Saud – you are correct, don’t worry.
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1.28 mol/dm3
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abel Reply:
March 29th, 2011 at 7:01 am
can you please be my personal tutor
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sean Reply:
April 28th, 2011 at 10:27 pm
Hi Abel,
If you based in Singapore, you can consider our Chemistry Classes for O and A-Levels.
Find out more information at http://www.WinnersEducation.com
Regards,
Sean Chua
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1.28 mol/dm3 (to 3 sf)
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Mr or H2SO4 = 98
98g H2SO4 = 1 MOL
50g H2SO4 = 0.51 MOL
1 MOL H2SO4 = 1 MOL HCL
0.51 MOL H2SO4 = 0.51 MOL HCL
NO OF MOL HCL IN 40OCM^3 WATER = 0.51 MOL
NO OF MOL HCL IN 100CM63 WATER = 1.275 MOL
THEREFORE CONCENTRATION = 1.275mol/dm^3
my method is rather kind of long but you can understand well right?
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I feel it is really fun for you guys to early tackle questions,as for me I think I’m still far away,even if I have much passion.
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