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O Level Chemistry & IP Chemistry Notes by 10 Year Series Author – Chemistry Specialist

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O Level Chemistry – More Questions on REDOX

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Now, let us continue with more exam-based questions on REDOX itself.

For those looking for more questions to practice for upcoming major examinations, you are going to enjoy this.

Question 1:
In which of the following reactions is the underlined substance reduced?
A. Cl2 + 2I– –> 2Cl- + I2
B. Zn + H2SO4 –> ZnSO4 + H2
C. Fe2+ + H2O2 –> Fe3+ + H2O
D. CuO + H2 –> Cu + H2O

Question 2:
Which conversion involves the smallest change in oxidation number of the underlined element?
A. C(s) –> CO2
B. NO3-(aq) –> NO2(g)
C. SO32-(aq) –> SO42-(aq)
D. MnO4-(aq) –> Mn2+(aq)

Question 3:
The oxidation states of chlorine in ClO4- and Cl2O are respectively
A. +1 and +3
B. +3 and +7
C. +7 and +1
D. +7 and +2

Question 4:
Which statement is true about oxidizing agents?
A. Their oxidation state is zero
B. They are easily oxidized
C. They never contain hydrogen
D. They readily accept electrons

Question 5:
What does an oxidizing agent do?
A. It turns acidified potassium dichromate (VI) green
B. It turns potassium manganate (VII) colorless
C. It turns Universal Indicator red
D. It turns aqueous potassium iodide brown

PS: Leave your suggested answers below at the “Comments Section” so that we can come in to share our suggested answers.

“Wanting Leads to Wanting, Doing Leads to Having”

Related Articles:

  • O Level Chemistry Question: Redox Reaction
  • O Level Chemistry: Redox Reaction Question 3
  • O Level Chemistry: Redox Reactions
  • O Level Chemistry – Qualitative Analysis
  • O Level Chemistry: Redox Reaction Question 5

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Comments

  1. chioma says

    March 2, 2013 at 2:25 am

    1:D 2:A 3:C 4:D 5:A

  2. Fixxa says

    October 18, 2011 at 6:26 pm

    i agree by ol da answerx buh wont da reaxon foh MCQ # 3 plx!

  3. Fixxa says

    October 18, 2011 at 6:23 pm

    1. D, the oxidation state of copper changes from +2 to 0.
    2. B, the oxidation state of Nitrogen changes from +6 to +4.
    3. C,
    4. D, oxidizing agents are themselves reduced. Hence, they accept electrons.
    5. D, aqueous potassium iodide is a reducing agent which itself is oxidized by any oxidizing agent.

  4. sean says

    September 15, 2008 at 9:44 pm

    Hello Jacq,

    Welll Done!

    Having a strong basic foundations is very impt for you to handle application questions.

    PS: Are you taking your O Levels this year?

    To Your Academic Success in Chemistry,
    Sean
    Master Trainer
    http://www.SimpleChemConcepts.com

  5. Jacq says

    September 14, 2008 at 3:48 pm

    1. D. CuO + H2 ?> Cu + H2O
    2. B. NO3-(aq) ?> NO2(g)
    3. C. +7 and +1
    4. D. They readily accept electrons
    5. D. It turns aqueous potassium iodide brown

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