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O Level Chemistry & IP Chemistry Notes by 10 Year Series Author – Chemistry Specialist

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O Level Chemistry Question: Periodic Table & Group Trends

Question from a Top School 2007 O Level Chemistry Prelim Paper:

Question:

Astatine is a Group VII element below Iodine in Periodic Table. Which of the following statements concerning Astatine is correct?

A) It is a liquid at room temp and pressure.
B) It is a stronger oxidizing agent than iodine
C) It reacts with sodium ti form an ionic compound
D) Its diatomic molecules are held together by weak covalent bonds

Should be a manageable question. Enjoy doing!

PS: Leave your suggested answers in the “Comments” section below.

Rgds
Sean

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Comments

  1. Sean Chua says

    October 9, 2007 at 4:29 pm

    Well Done Lijun and Anonymous.
    Answer is indeed C.

    Keep up the good work!

    Chem Prac in two days time.
    All the Best!

    Rgds
    Sean
    SimpleChemConcepts
    “Learning Experience with A Difference”

  2. Anonymous says

    October 7, 2007 at 12:33 pm

    C. Sodium is a metal and astatine is a non metal (under halogens group) so they go through ionic bonding to form ionic compounds.

    I’m not sure about A, so I left it out first.

    B)Iodine is more reactive than Astatine, this makes it a stronger oxidising agent. I’m not sure whether this theory is right.

    D)It is a diatomic molecule, but covalent bonds are strong. It’s the intermolecular forces of attraction that are weak.

    So by comparison, C sounds like a more logical answer than A. Do correct me if I’m wrong though.

  3. lijun(: says

    October 7, 2007 at 10:12 am

    i think the answer is C.

    since it’s below iodine, it should be a solid at rtp. so it can’t be A.

    also, the higher the halogen in the group, the more reactive it is. so iodine should be a stronger oxidizing agent than astatine. so it’s not B.

    it’s diatomic molecules are held together by weak van der waals forces, not weak covalent bonds. thus not D.

    since it’s in group VII, its ion has a charge of -1. thus will form ionic compound with sodium, which has a charge of +1. forming NaAt.

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