Halo, Try this one…on? Reduction & Oxidation (Redox Reactions).
Q) A drop of solution S turns acidified orange potassium dichromate (VI) to green chromium (III) ions. What must solution S contain?
A) An acid
B) An oxidizing agent
C) A reducing agent
D) A substance that can be oxidized
Come on students…. Leave your suggested answer in the “Comments” section below.
Rgds,
Sean
S changed orange potassium dichromate (vi)to green potassium dichromate (iii).Therefore the solution must be containing an oxidizing agent.
yupp C is the answer
ily this site soo far 🙂
It’s definitely C.
Well Done both.
Answers is indeed C. Some students tends to have problems when it comes to Reducing and Oxidizing Agents.
i think its C too.
S reduces the orange potassium dichromate (VI) to green potassium dichromate (III),
hence, S must be a reducing agent.
I think the answer is C.. by the way, can I have the link that was removed in the comments in the post on Fats and Terylene?
Orange potassium dichromate (VI) is reduced to green chromium (III) ions, so it’s an oxidizing agent.
Hence, the solution must be a reducing agent…
C?
Is it C?